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java异步方式实现登录_java

作者:用户 来源:互联网 时间:2016-05-22 10:52:05

java登录异步

java异步方式实现登录_java - 摘要: 本文讲的是java异步方式实现登录_java, 本文实例为大家分享了java异步登录的具体代码,供大家参考,具体内容如下 1.LoginServletAjax.java   package com.scce.servlet; import java.io.IOExceptio

本文实例为大家分享了java异步登录的具体代码,供大家参考,具体内容如下

1.LoginServletAjax.java  

package com.scce.servlet;
 
import java.io.IOException;
import java.io.PrintWriter;
 
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
 
import net.sf.json.JSONObject;
 
import com.scce.dao.AdminUserDao;
import com.scce.pojo.AdminUser;
 
public class LoginServletAjax extends HttpServlet {
 
  @Override
  protected void service(HttpServletRequest request,
      HttpServletResponse response) throws ServletException, IOException {
    // TODO Auto-generated method stub
    request.setCharacterEncoding("utf-8");
    response.setContentType("text/html;charset=utf-8");
    String method = request.getMethod();
    if (method.equals("POST")) {
      doLoginAjax(request, response);
    } else if (method.equals("GET")) {
 
    }
 
  }
 
  public void doLoginAjax(HttpServletRequest request,
      HttpServletResponse response) throws ServletException, IOException {
     PrintWriter out = response.getWriter();
   
    // 用户名
    String username = request.getParameter("username");
    // 密码
    String password = request.getParameter("password");   
    String msg = "";
    AdminUserDao adminUserDao = new AdminUserDao();
    AdminUser adminUser = adminUserDao.queryUser(username, password);
    if (adminUser != null) {
       
        msg="登录成功!";
      String jsonObj=   JSONObject.fromObject(adminUser).toString();
      out.print("{\"Msg\":\""+msg+"\",\"rows\":"+jsonObj+"}");
      System.out.println("{\"Msg\":\""+msg+"\",\"rows\":"+jsonObj+"}");
     
    } else {
      msg="用户名或者密码不正确!";
      out.print("{\"Msg\":\""+msg+"\"}");
    }
     
     
    out.flush();
    out.close();
 
  }
 
}

2.test2.html

<!DOCTYPE html>
<html>
  <head>
    <title>chapter3-test2</title>
 
    <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
    <meta http-equiv="description" content="this is my page">
    <meta http-equiv="content-type" content="text/html; charset=UTF-8">
 
 
 
    <link rel="stylesheet" href="../UI/themes/icon.css" type="text/css"></link>
 
    <link rel="stylesheet" href="../UI/themes/default/easyui.css"
      type="text/css"></link>
 
    <!-- <script type="text/javascript" src="../js/jquery-1.8.2.min.js"></script> -->
    <script type="text/javascript" src="../UI/jquery.min.js"></script>
    <script type="text/javascript" src="../UI/jquery.easyui.min.js"></script>
 
    <script type="text/javascript" src="../UI/locale/easyui-lang-zh_CN.js"></script>
 
    <script type="text/javascript">
  //string number boolean null object undefined function 
  $(function() {
    $("#LoginAdd").dialog({
      title : "用户登录",
      collapsible : 'true',
      width : 300,
      height : 200,
      buttons : [ {
        text : '登录',
        iconCls : 'icon-add',
        handler : function() {
          console.info("用户登录!");
          ajaxFrm();//ajax提交表单的函数
        }
      } ]
    });
 
  });
  function ajaxFrm() {
    //------------------------注释的是ajax提交方法----------------------------
    var LoginList = $("#LoginList");
     
    $.ajax({
      url : '../LoginServletAjax?tag=test',//相对路径访问
      type : 'POST', //提交请求的方式
      data : $('#form1').serialize()+'&names=liuqin&age=26',//将表单参数序列化,发送到服务器的数据(提交额外的参数)
      dataType : 'json', //预期服务器返回的数据类型-json object  
      success : function(data) {//请求成功后将调用此方法var data = {"Msg":"登录成功","rows":{"username":"admin",...}}
        console.info(data);//调试代码
        $.messager.alert("提示", data.Msg);
        LoginList.html("");//清空数据
        if (data.rows) {
          var stra = LoginList.html() + "用户名:" + data.rows.username
              + "--密码:" + data.rows.password + "<br/>";
          LoginList.html(stra);
        }
      },
      error : function(error) { //请求失败时将调用此方法
        console.info(error);
 
      }
    });
 
     /*var LoginList = $("#LoginList");
     $("#form1").form("submit", {
       url: "../LoginServletAjax?tag=test",
       onSubmit: function (param) { //提交额外的参数
         param.name="liuqin";
       param.age=27;
         var username = $("#username").val();
         var password = $("#password").val();
         if (username.length == 0 || password.length == 0) {
           $.messager.alert('警告', '请输入用户名和密码');
           return false;
         }
         return true;
       },
       success: function (data) { 
         //var data = eval('(' + data + ')'); 
         var data = $.parseJSON(data);//服务器端返回json字符串转成json对象-js object
         console.info(data);
         $.messager.alert("提示", data.Msg);
         LoginList.html("");//清空数据
          if (data.rows) {
            var stra = LoginList.html() + "用户名:" + data.rows.username
                + "--密码:" + data.rows.password + "<br/>";
            LoginList.html(stra);
          }
       }
     });*/
 
  }
</script>
  </head>
 
  <body>
 
 
    <div id="LoginAdd">
      <form id="form1" method="post">
        <table style="width: 100%;">
          <tr>
            <td>
              用户名:
            </td>
            <td>
              <input id="username" name="username"
                class="easyui-validatebox textbox">
            </td>
          </tr>
          <tr>
            <td>
              密码:
            </td>
            <td>
              <input id="password" name="password"
                class="easyui-validatebox textbox" type="password">
            </td>
          </tr>
        </table>
      </form>
    </div>
    <div id="LoginList">
      用户信息加载中......
    </div>
 
    <video width="320" height="240" controls="controls"
      src="../video/B4934A0C53FC55703BFE3F6843E66166.mp4" type="video/mp4">
      Your browser does not support the video tag.
    </video>
 
 
  </body>
</html>

以上就是本文的全部内容,希望对大家学习java程序设计有所帮助。

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