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# PHP 和 Python实现Project Euler 1、2题

PHP 和 Python实现Project Euler 1、2题，有需要的朋友可以参考下。

Problem 1

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

PHP版本 ：

`/** * @desc Project Euler 1 * @Author tina * @Date 2015-08-27 */\$sum = 0;for(\$i=0; \$i<1000; \$i++){    if((\$i%3 == 0) || (\$i%5 == 0)){\$sum += \$i;    }}echo \$sum;`
python版本：

`sum = 0for i in range(1000):    if((i%3 == 0) or (i%5 == 0)):sum += iprint sum`
Problem 2

Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be:

1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ...

By considering the terms in the Fibonacci sequence whose values do not exceed four million, find the sum of the even-valued terms.

PHP版本：

`/** * @desc : Project Euler 2 * @Author : tina  * @Date : 2015-08-27 */\$fab1 = 1;\$fab2 = 1;\$sum = 0;do{    \$fab = \$fab1+\$fab2;    \$fab1 = \$fab2;    \$fab2 = \$fab;    if(\$fab%2 == 0){\$sum += \$fab;    }}while(\$fab < 4000000);echo \$sum;`

python版本：

`fab1 = 1fab2 = 1sum = 0while True :    fab = fab1+fab2    fab1 = fab2    fab2 = fab    if(fab%2 == 0):sum += fab    if(fab > 4000000) : breakprint sum`

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