linux shell 统计一文件中某一字符串出现的次数

0
总编总编 2年前
sunshine@debian :~$ cat test.txt
hello,let us have a try,now,begin,
sunshine@debian :~$ j=","
sunshine@debian :~$ echo $j
,
sunshine@debian :~$ awk -v RS="@#$j" '{print gsub(/,/,"&")}' test.txt
4
sunshine@debian :~$

看懂了吧，-v参数 引用外部变量j，gsub返回指定字符被替换的次数

 

给你贴个awk的man：

 gsub(r,s,t)  gsub(r,s) 
                     Global  substitution,  every  match  of  regular expression r in variable t is replaced by string s.  The number of replacements is 
                     returned.  If t is omitted, $0 is used.  An & in the replacement string s is replaced by the matched substring of t.  \& and \\ put 
                     literal & and \, respectively, in the replacement string.