SQL 表A(id,no,name)、表C(no)怎么判断每个人缺少的no并且把缺少的新增进表A

create table ma(
id int,
fe varchar(20),
vname varchar(20)
);
insert into ma values(1,'A','张三');
insert into ma values(1,'B','张三');
insert into ma values(2,'A','李四');
insert into ma values(3,'B','王五');
create table mb(
fe varchar(20)
);

insert into mb values('A');
insert into mb values('B');
insert into mb values('C');
insert into ma(id,fe,vname) values(
SELECT id,vname,fe FROM (
select c.*,c.vname + ','+c.fe as kid from (
select * from
(
select distinct id,vname from ma
) a,
(select fe from mb)
b
) c
) D
where kid not in(SELECT VNAME+','+FE FROM ma)
)