java后台如何解析这样的json串？jsonObject和JsonArray不好用，有别的方式吗

创建对象的方法可以试试；或者用map也可以。

public static void ParseJson(String jsonString) {

    // 以employee为例解析，map类似
    JSONObject jb = JSONObject.fromObject(jsonString);
    JSONArray ja = jb.getJSONArray("user");
    List<Offers> userList = new ArrayList<Offers>();
    // 循环添加User对象（可能有多个）
    for (int i = 0; i < ja.size(); i++) {
        Offers user = new Offers();
        user.setName(ja.getJSONObject(i).getString("name"));
        user.setSex(ja.getJSONObject(i).getString("sex"));
        user.setAge(ja.getJSONObject(i).getInt("age"));
        userList.add(user);
    }
    System.out.println("\n将Json数据转换为User对象：");
    for (int i = 0; i < userList.size(); i++) {
        Offers user = userList.get(i);
        System.out.println("age: " + user.getAge() + "\nname: "
                + user.getName() + "\nsex: " + user.getSex());
    }    

    // map:
    JSONArray JMap = jb.getJSONArray("map");

    List<Map<String, Object>> mapList = new ArrayList<Map<String,Object>>();
    Map<String, Object> maps = null;

    for (int i = 0; i < JMap.size(); i++) {
        maps = new HashMap<String, Object>();

        maps.put("name", JMap.getJSONObject(i).get("name"));
        maps.put("sex", JMap.getJSONObject(i).get("sex"));
        maps.put("age", JMap.getJSONObject(i).get("age"));

        mapList.add(maps);
    }

    System.out.println("\n将Json数据转换为Map类型");
    for (int i = 0; i < mapList.size(); i++) {
        Map<String, Object> map = mapList.get(i);
        System.out.println("age: " + map.get("age") + "\nname: "
                + map.get("name") + "\nsex: " + map.get("sex")); 
    }
}