请教一下这段代码哪里出错了？
#include <stdio.h>
#include <stdlib.h>
typedef int Elemtype;
typedef struct node{
Elemtype elem;
struct node *next;
}*top;
int m=sizeof(struct node);
struct node *Push(struct node *top,Elemtype x){
struct node *p;
p=(struct node *)malloc(m);
p->next=top;
top=p;
p->elem=x;
return top;
}
struct node *Pop(struct node *top,Elemtype &x){
if(top==NULL) return 0;
struct node *p;
p=top;
x=p->elem;
top=top->next;
delete p;
return top;
}
Elemtype GetTop(struct node *top){
if(top==NULL) return -1;
int x=top->elem;
return x;
}
int main(){
struct node *p;
int x=0,y=0;
Push(p,2);
Push(p,34);
Pop(p,x);
printf("%d",x);
y=GetTop(p);
return 0;
}然后用g++编译通过，但是运行程序时出现提示：
LinkStack(14073,0x7fff7729d300) malloc: * error for object 0x7fff55c40b00: pointer being freed was not allocated
* set a breakpoint in malloc_error_break to debug
Abort trap: 6
请问这是怎么回事？
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#include <stdio.h> #include <stdlib.h> typedef int Elemtype; typedef struct node{ Elemtype elem; struct node *next; }; struct node * top; int m=sizeof(struct node); struct node *Push(Elemtype x){ struct node *p; p=(struct node *)malloc(m); p->next=top; top=p; p->elem=x; return top; } struct node *Pop(Elemtype &x){ if(top==NULL) return 0; struct node *p; p=top; x=p->elem; top=top->next; delete p; return top; } Elemtype GetTop(){ if(top==NULL) return -1; int x=top->elem; return x; } int main(){ top=(struct node *)malloc(sizeof(struct node)); int x=0,y=0; Push(2); Push(34); Pop(x); printf("%d",x); y=GetTop(); return 0; }2019-07-17 19:12:06赞同 展开评论 打赏
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