企业面试题1：
已知下面的字符串是通过RANDOM随机数变量md5sum|cut-c 1-8截取后的结果，请破解这些字符串对应的md5sum前的RANDOM对应数字？
21029299
00205d1c
a3da1677
1f6d12dd
890684b
解题思路：通过每次传递一个参数的方式，来实现依次破解
$RANDOM的范围为0-32767
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#!/bin/bash
#Author: liuwei
#Site: www.51liuzw.com
for
n
in
{0..32767}
do
MD5=`
echo
$n | md5sum |
cut
-c 1-8`
if
[
"$MD5"
==
"$1"
];
then
echo
"$n is."
exit
else
echo
"$n no."
fi
done
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注：也可以通过定义数组的方法，来一次全部对比
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#!/bin/bash
#Author: liuwei
#Site: www.51liuzw.com
array=(
00205d1c
21029299
a3da1677
1f6d12dd
890684b
)
for
n
in
{0..32767}
do
MD5=`
echo
$n | md5sum |
cut
-c 1-8`
for
i
in
${array[@]};
do
if
[
"$MD5"
==
"$i"
];
then
echo
"$n and $i"
>> c.log
break
else
echo
"$n no."
fi
done
done
|
#cat c.log
1346 and 00205d1c
7041 and 1f6d12dd
25345 and a3da1677
25667 and 21029299
企业面试题2：批量检查多个网站地址是否正常
要求：shell数组方法实现，检测策略尽量模拟用户访问思路
http://www.baidu.com
http://www.taobao.com
http://www.51liuzw.com
http://192.168.50.199
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#!/bin/bash
#Author: liuwei
#Site: www.51liuzw.com
array=(
http:
//www
.baidu.com
http:
//www
.taobao.com
http:
//www
.51liuzw.com
http:
//192
.168.50.199
)
for
n
in
${array[*]};
do
URL=`curl -I -m 2 $n 2>
/dev/null
|
egrep
"200|302"
|
wc
-l`
if
[
"$URL"
-
eq
1 ];
then
echo
"$n is OK"
else
echo
"$n is not OK"
fi
done
|
结果：
#sh test.sh
http://www.baidu.com is OK
http://www.taobao.com is OK
http://www.51liuzw.com is not OK
http://192.168.50.199 is not OK
企业面试题3：：用shell处理以下内容
1、按单词出现频率降序排序！
2、按字母出现频率降序排序！
the squid project provides a number of resources toassist users design,implement and support squid installations. Please browsethe documentation and support sections for more infomation
1.按单词出现频率降序排序！
解决思路：把空格换为换行符，并排序统计
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#sed 's# #\n#g' c.txt | sort | uniq -c
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2.按字母出现频率降序排序！
解决思路：使用grep -o "\w"，把单词拆开并去除种各符号
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1
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#cat c.txt | grep -o "\w" | sort | uniq -c
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本文转自激情燃烧的岁月博客51CTO博客，原文链接http://blog.51cto.com/liuzhengwei521/1773814如需转载请自行联系原作者
weilovepan520
