备份前一天（确切说是24小时前）数据的脚本

#!/bin/bash
Date=`date +%m%d%y -d "1 day ago"`

Date2=20`date +%y/%m/%d`-

Date3=`date +%H:%M:%S`

Date4=`date +%M`

mkdir /history/aa/$Date
touch /log/aa/$Date.log
echo "aa backup begin at $Date2$Date3" >> /log/aa/$Date.log
find /backup/aa/ -type f -mtime 1 -exec cp -av {} /history/aa/$Date/ \;

find /history/aa/ -type d -mtime 1 -empty -exec rmdir {} \;

Date5=20`date +%y/%m/%d`-

Date6=`date +%H:%M:%S`

Date7=`date +%M`

Date8=$(($Date7-$Date4))

echo "aa backup end at $Date5$Date6" >> /log/aa/$Date.log

echo "aa backup use time $Date8 minutes" >> /log/aa/$Date.log

/usr/bin/mail -s "aa backup done" aa@ming.com < /log/aa/$Date.log

不足：脚本需在0：00执行，否则24小时不能代表完整一天

本文转自linux博客51CTO博客，原文链接http://blog.51cto.com/yangzhiming/1369867如需转载请自行联系原作者

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