js 获取请求地址中的参数

js中如何获取浏览器请求地址中的参数呢?

js获取请求的query string

Js代码  

1. var getPageParams = function(){  
2.             var i,ilen,strs,keyName,keyValue,  
3.                     params={},  
4.                     path = window.location.pathname,  
5.                     url = window.location.href;  
6.             if(url.indexOf("?")>-1){  
7.                 var index=url.indexOf("?");  
8.                 strs=url.substring(index+1);  
9.                 console.log(strs);  
10.                 strs=strs.split("&");  
11.                 ilen=strs.length;  
12.                 for(i=0;i<ilen;i++){  
13.                     var indexEqual=strs[i].indexOf('=');  
14.                     keyName=strs[i].substring(0,indexEqual);  
15.                     keyValue=strs[i].substring(indexEqual+1);  
16.                     if(keyName=="callback") keyValue=decodeURIComponent(keyValue);  
17.                     params[keyName]=keyValue;  
18.                 }  
19.             }  
20.              
21.             return params;  
22.         };  
23.         console.log(getPageParams());  

请求地址为:http://localhost:63342/chanjet_web_js/chanjet/js/test_whuang.html?callback=http://www.weixin.com?id=123&app=weixin

时,运行结果:

Object {callback: "http://www.weixin.com?id=123", app: "weixin"}

http://localhost:63342/chanjet_web_js/chanjet/js/test_whuang.html?callback=http://www.weixin.com?id=123&app=weixin&returnurl=http://www.baidu.com 

运行结果:

Object {callback: "http://www.weixin.com?id=123", app: "weixin", returnurl: "http://www.baidu.com"}