SQL> select level, employee_id ,manager_id ,first_name ,last_name
2 from emp
3 start with employee_id =1
4 connect by prior employee_id = manager_id
5 order by level;
LEVEL EMPLOYEE_ID MANAGER_ID FIRST_NAME LAST_NAME
---------- ----------- ---------- ---------- ----------
1 1 James Smith
2 10 1 Kevin Black
2 2 1 Ron Johnson
2 4 1 Susan Jones
3 13 10 Doreen Penn
3 7 4 John Grey
3 11 10 Keith Long
3 5 2 Rob Green
3 3 2 Fred Hobbs
3 12 10 Frank Howard
3 6 4 Jane Brown
4 8 7 Jean Blue
4 9 6 Henry Heyson
已选择13行。
已用时间: 00: 00: 00.04
SQL> select count(distinct level)
2 from emp
3 start with employee_id =1
4 connect by prior employee_id =manager_id;
COUNT(DISTINCTLEVEL)
--------------------
4
已用时间: 00: 00: 00.00
SQL> set pagesize 999
SQL> col employee for a25
SQL> select level,
2 lpad('-',2*level-1) || first_name ||' '|| last_name as employee
3 from emp
4 start with employee_id =1
5 connect by prior employee_id =manager_id;
LEVEL EMPLOYEE
---------- -------------------------
1 -James Smith
2 -Ron Johnson
3 -Fred Hobbs
3 -Rob Green
2 -Susan Jones
3 -Jane Brown
4 -Henry Heyson
3 -John Grey
4 -Jean Blue
2 -Kevin Black
3 -Keith Long
3 -Frank Howard
3 -Doreen Penn
已选择13行。
