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## HDOJ 1076 An Easy Task（闰年计算）

Problem Description
Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?

Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.

Note: if year Y is a leap year, then the 1st leap year is year Y.

Input
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains two positive integers Y and N(1<=N<=10000).

Output
For each test case, you should output the Nth leap year from year Y.

Sample Input
3
2005 25
1855 12
2004 10000

Sample Output
2108
1904
43236

Hint：
We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.

``````import java.util.Scanner;

public class Main{
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int t = sc.nextInt();
while(t-->0){
int year = sc.nextInt();
int n = sc.nextInt();
int nyear = 0;
if((year%4==0&&year%100!=0)|(year%400==0)){
nyear=1;
}//如果year是闰年，nyear就加一
while(nyear<n){//当nyear小于n时，就循环
year++;
if((year%4==0&&year%100!=0)|(year%400==0)){
nyear++;
}//year是闰年，nyear就加加
}
System.out.println(year);
}
}

}
``````

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