HDOJ 1076 An Easy Task(闰年计算)

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HDOJ 1076 An Easy Task(闰年计算)

谙忆 2016-04-01 16:35:00 浏览705
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Problem Description
Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?

Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.

Note: if year Y is a leap year, then the 1st leap year is year Y.

Input
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains two positive integers Y and N(1<=N<=10000).

Output
For each test case, you should output the Nth leap year from year Y.

Sample Input
3
2005 25
1855 12
2004 10000

Sample Output
2108
1904
43236

Hint:
We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.

题意就是:输入一个年份year和一个n,求这个year之后的第n个闰年,
如果year是闰年,则算第一个闰年。

直接暴力做,并没有超时。

import java.util.Scanner;

public class Main{
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();
        while(t-->0){
            int year = sc.nextInt();
            int n = sc.nextInt();
            int nyear = 0;
            if((year%4==0&&year%100!=0)|(year%400==0)){
                nyear=1;
            }//如果year是闰年,nyear就加一
            while(nyear<n){//当nyear小于n时,就循环
                year++;
                if((year%4==0&&year%100!=0)|(year%400==0)){
                    nyear++;
                }//year是闰年,nyear就加加
            }
            System.out.println(year);
        }
    }

}

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