【JAVA大数训练】A + B Problem II

A + B Problem II
Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 196702    Accepted Submission(s): 37626

Problem Description
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each

line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process

them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second

line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a

blank line between two test cases.

Sample Input
2
1 2
112233445566778899 998877665544332211
 

Sample Output
Case 1:
1 + 2 = 3

Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110

import java.math.BigInteger;
import java.util.Scanner;
public class Main {
 public static void main(String[] args) {
  Scanner input=new Scanner(System.in);
  int n=input.nextInt();
  int k=1;
  while(n!=0)
  {
   BigInteger a=input.nextBigInteger();
   BigInteger b=input.nextBigInteger();
      BigInteger c=a.add(b);
                    n--;
      if(k!=1)
       System.out.println();//输出换行
            System.out.println("Case "+k+":");
            k++;
      System.out.println(a+" + "+b+" = "+c);
  }
 }
}